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X^2-80X+200=0
a = 1; b = -80; c = +200;
Δ = b2-4ac
Δ = -802-4·1·200
Δ = 5600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5600}=\sqrt{400*14}=\sqrt{400}*\sqrt{14}=20\sqrt{14}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-80)-20\sqrt{14}}{2*1}=\frac{80-20\sqrt{14}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-80)+20\sqrt{14}}{2*1}=\frac{80+20\sqrt{14}}{2} $
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